I "knit on" with confidence. Or something like that.
Here's how the logic panned out yesterday: if one skein does 11 plus ridges, 9 skeins would make 90 (plus) ridges and I have enough yarn. (I need 70 ridges.) So I kept on knitting.
After running out of brown, and knitting in the "thumb trick" that marks the fold lines, I realized that I wanted to be weaving rust to rust. So I needed to "center" the blue around the top of the shoulder. Calculating ensued. Verdict unknown.
Today's dilemma is to figure out if there will be enough yarn for an icord border. (And will it be of one color?) If one skein does 11 ridges (22 rows) of 70 stitches per row, that is 1540 stitches per skein. I need to pick up one stitch per cast on stitch (70) , plus one per ridge (70) each side (another 70) plus a few extra for making square turns around the corner (210 total pickup stitches plus a few). If I do a 2 stitch icord (vs 3 stitch, because it is bulky yarn) that would be 3 stitches knit for each icord "stitch". 3 x 210 is 630 (plus a few for those corners). That's about 1/2 skein of yarn. Right?